Lesson 2.1 - Momentum
VIDEO LESSON (15:21 min)
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Newton's formulation of his law was:
2) a \( 1750kg \) car travelling at \( 95 km/h \) [W].
Is \( \vec{F} = \frac{ \Delta \vec{p} }{ \Delta t } \) the same as \( \vec{F} = m \vec{a} \)?
IMPULSE:
The product of the avearge force exerted and the time interval is called the impulse.
SOLUTION:
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RECALL: NEWTON'S SECOND LAW
Newton's formulation of his law was:
where,
\( \vec{p} \) is an objects momentum measure in \( kg \cdot m/s \) (or \( N \cdot s \))
DETERMINE THE MOMEMTUM OF THE FOLLOWING OBJECTS:
1) A \( 500g \) ball travelling at \( 50 m/s \) [forward].2) a \( 1750kg \) car travelling at \( 95 km/h \) [W].
Is \( \vec{F} = \frac{ \Delta \vec{p} }{ \Delta t } \) the same as \( \vec{F} = m \vec{a} \)?
IMPULSE:
The product of the avearge force exerted and the time interval is called the impulse.
EXAMPLE PROBLEM #1
A golf ball is struck with a force of \( 6.0 \times 10^3 N \). The club and the ball are in contact for \( 3.5 \times 10^{-4} s \). Determine the impulse on the golf ball.SOLUTION:
IMPULSE-MOMENTUM THEOREM
EXAMPLE PROBLEM #2
A puck is shot at \( 45 m/s \) at a goalie and is rebounded in the opposite direction with a velocity of \( 23 m/s \). Determine the impulse on the puck, \( m = 170 g \).
SOLUTION:
Last modified: Sunday, 18 May 2025, 4:29 PM